. The population of a city is 154250. If it increases at the rate of 10% per annum what will be population 2
years hence?
(A) 186642; 127479
(B) 156641; 127478
(C) 164789; 145894
(D) 254879; 855457
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Answer:
sorry but the question is incorrect.
Step-by-step explanation:
population after 2 year if it is you mean
than,
the process of solving it is same as solving the compound interest.
just do,
154250[1+10/100]^2
154250×(110/100)×(110/100)
(154250×11×11)/10×10
do this and get your result.
HOPE IT HELP
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