Question

The population of a city is 160,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?

Answer 1

$Present \: population \: of \: a \:city \blue{(P)}\\= 160000$

$Increase \:rate \: of \: population (g) = 6\% \: p.a$

$Number \:of \: years (n) = 2$

$\boxed { \pink { Population \: after \:n \: years= P\Big( \frac{100+ g}{100}\Big)^{n}}}$

$\red { Population \: after \:2 \: years} \\= 160000\Big( \frac{ 100+6}{100}\Big)^{2} \\= 160000 \times \frac{106}{100} \times \frac{106}{100} \\= 16 \times 106 \times 106 \\= 179,776$

Therefore.,

$\red{ Population \: after \:2 \: years\:in \:the \:city } \\\green {= 179,776}$

•••♪