Question

The population of a city is 20,000 in the year 2008. It is increased at the rate of 10% per annum. What will be the population of the city in the year 2010?

4200
22000
24200
42000​

Answer 1

Answer:

24200

Step-by-step explanation:

population, p at 2008 = 20000

rate of increment, r     = 10%

years (2010-2008)  ,n = 2years

therefore, population after 2 years,  = p(1+$\frac{r}{100}$)ⁿ

                                                               = 20000(1+$\frac{10}{100}$)²

                                                               = 20000($\frac{110}{100}$)²

                                                               = 20000*$\frac{11}{10}$*$\frac{11}{10}$

                                                               = 200*121

                                                               = 24200