the population of a city is 200 000. if the annual birth rate and the annual death rate are 6% and 3% respectively then calculate the population of the city after 2 years.
Answers
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Original population = 2,00,000
Birth rate = 6%
Death rate = 3%
Number of births = ( 6 ÷ 100 ) × ( 2,00,000 )
Number of birth = ( 6 ) × ( 2000 )
Number of births = 12000
Number of deaths = ( 3 ÷ 100 ) ( 2,00,000 )
Number of deaths = ( 3 ) × ( 2000 )
Number of deaths = 6000
Population after a year = 2,00,000 - 6,000 + 12,000
Population after a year = 2,06,000
Number of births = ( 6 ÷ 100 ) × ( 2,06,000 )
Number of births = ( 6 ) × ( 2060 )
Number of births = 12,360
Number of deaths = ( 3 ÷ 100 ) × ( 2,06,000 )
Number of deaths = ( 3 ) × ( 2060 )
Number of deaths = 6,180
Population after the 2nd year = 2,06,000 - 6,180 + 12,360
Population after the second year = 2,12,180
The required answer = 2,12,180
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Original population = 2,00,000
Birth rate = 6%
Death rate = 3%
Number of births = ( 6 ÷ 100 ) × ( 2,00,000 )
Number of birth = ( 6 ) × ( 2000 )
Number of births = 12000
Number of deaths = ( 3 ÷ 100 ) ( 2,00,000 )
Number of deaths = ( 3 ) × ( 2000 )
Number of deaths = 6000
Population after a year = 2,00,000 - 6,000 + 12,000
Population after a year = 2,06,000
Number of births = ( 6 ÷ 100 ) × ( 2,06,000 )
Number of births = ( 6 ) × ( 2060 )
Number of births = 12,360
Number of deaths = ( 3 ÷ 100 ) × ( 2,06,000 )
Number of deaths = ( 3 ) × ( 2060 )
Number of deaths = 6,180
Population after the 2nd year = 2,06,000 - 6,180 + 12,360
Population after the second year = 2,12,180
The required answer = 2,12,180