Math, asked by kushikachhabra, 11 months ago

The population of a city is 50,000 at present. It decreases at the rate of 10% per annum. What was its population
4 years ago from present

Answers

Answered by sreehasinimarturi
1

Answer:

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Step-by-step explanation:

Total population in year x = 50000.

If growth rate is 20% of population.

So, population in year (x+1) = 50000+ 20% of 50000

= 50000 + 10000

= 60000. This is Net Population.

Now,

For the succeeding year,

New net population = 60000 + 20% of 60000

= 60000 + 12000

= 72000. This is the new net population.

Hence 72000 is the correct answer.

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Answered by sainathbalajiajane
0

Step-by-step explanation:

20497

Population after 4 years = present population (1+

100

r)

n

Population after 4 years = 14000×(1+

100

10

)

4

=14000×1.4641

=20497

Population after 4 years =20497

was answer helpful

Mark as brainly plz

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