Question

The population of a city was 2,25,000 in the year 2017. It increased at the rate of 10% p.a. Find the population at the end of the year 2020. ​

Answer 1

Let the population before two years ago be x

Given the population increases by 10%

So increase in population after one year is

100

10

×x=0.1x

So population after one year is x+0.1x=1.1x

Increase in population after another one year is

100

10

×1.1x=0.11x

So population at present is 1.1x+0.11x=1.21x

But given population at present is 3,02,500

⟹1.21x=302500

⟹x=

1.21

302500

=2,50,000

Population of city two years ago is 2,50,000

Answer 2

Answer:

The population at the end of the year 2020 will be 2,99,475