Question

The population of a city was 422500 in the year 2010.If it increases at the rate of 4percent per annum,find
1) population of the town in 2012.
2) population of the town in 2008.

Answer 1

Answer:

1)456976

2)390625

Step-by-step explanation:

1)

  In the year 2010 , population = 422500

  In the next year 2011, population = 422500+((422500*(4/100))=439400

  In the next year 2012, population =439400+((439400*(4/100))=456976

2)

  In the year 2010 , population = 422500

   In the year 2009 , population = x

                  x+(4x/100)=422500

                  104x=422500*100

                   x=42250000/104

                      =406250

  in the year 2008, population = y

                 y+(4y/100)=406250

                 104y=406250*100

                  y=40625000/104

                     =390625.