Question

The population of a city was 84500 and rose to 1,11,200 in 1981. Find the percentage increase in the population.

Answer 1

hola^_^

your answer is - - - - -

population was=84500

it rose to=111200

population increased=111200-84500=26700

increased%=(total amount increased/initial value×100)

increase%=31.59%

Answer 2

Given - Original and New Percentage

Find - Percentage increase

Solution - Percentage increase = change in percentage/original Percentage*100

Percentage increase =

$\frac{(1,11,200 - 84500) \times 100}{84500}$

Performing subtraction

Percentage increase =

$\frac{26700 \times 100}{84500}$

Cancelling zero and performing division

Percentage increase = 31.6%.