the population of a city was120000in the year 2013.during next year it increased by 6percent but due to an epidemic it decreased by 5percent in the following year . what was its present population in the year 2015
Answers
Answered by
71
population on 2015=120000×106/100×95/100
=12×106×95
=120840
The population in 2015 is increased by 840
percentage=100×840/120000
=0.7%
so the population increase by 0.7%
=12×106×95
=120840
The population in 2015 is increased by 840
percentage=100×840/120000
=0.7%
so the population increase by 0.7%
Answered by
132
Answer:120840
Solution:
Population in 2013 =120000
It increased at the rate of 6%
Population in 2014 = P(1+ R/100)n
=120000 (1 +6/100)1
=120000 (53 /50 )
= 127200
Therefore,Population in 2014 =127200
It decreased at the rate of 5%
Population in 2015 =P(1- R/100)n
= 127200 (1-5/100)1
=127200 (19/20)
=120840
Hence, population in 2015 was 120840.
Hope this answer would be better.
Similar questions