Question

the population of a city was225000 at 2018 if it will increaseat the rate of 12% next year what will be the population in 2019​

Answer 1

Answer:

225000/100*12

2250*12

27000

225000+27000

252000

Ans.=252000 People

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Answer 2

The population in 2019 will be 252000.

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Let's understand a few concepts:

If "P" is the population at the beginning of a certain year and the constant rate of growth is "R%" per annum then the population after "n" years will be:

$\boxed{\bold{Population\:after\:"n"\:years \:= \:P \bigg[1 + \frac{R}{100}\bigg]^n }}$

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Let's solve the given problem:

The population of the city in the year 2018 was = 225000

The rate of increase in the population = 12%

The no. of years of increase in population (2018 to 2019) = 1 year

Therefore, by using the above formula, we get

The population of the city in the year 2019 will be,

= $225000\times \bigg [1 + \frac{12}{100}\bigg]^1 }$

= $225000\times \bigg [ \frac{100 + 12}{100}\bigg]^1 }$

= $225000\times \frac{1 12}{100}\bigg }$

= $\frac{25200000}{100}\bigg }$

= $\bold{252000}$

Thus, the population in 2019​ will be 252000.

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