The population of a country increased by an average of 2% per year from 2000 to 2003. If the population of this country was 2 000 000 on December 31, 2003, then the population of this country on January 1, 2000, to the nearest thousand would have been
A. 1 846 000
B. 1 852 000
C. 1 000 000
D. 1 500 000
Answers
Answer:
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Step-by-step explanation:
your answer
ANSWER
⇒ Let population of the country on one 1stJan,2000 be P
2000
.
⇒ Population on 31stDec,2003(P
2003
=2,000,000
⇒ Increase =2%=0.02
⇒ Final population after n years =(1+0.02)
n
=(1.002)
n
According to the question,
⇒ P
2003
=(1.02)
4
P
2000
[ As the 2000 to 2003 will be 4 years ]
⇒ P
2000
=
(1.02)
4
P
2003
=
(1.02)
4
2,000,000
=1847690.85
∴ Here, nearest thusand would be 18,47,000
Answer:
Step-by-step explanation:
population of the country on Jan 1, 2000 = P
r = 2%
total duration = 4 years, : 2000, 2001, 2002, 2003
If we take the compounding of the rate of growth :
2, 000, 000 = P (1 + 2/100)^4 = P (1.02)^4
P = 1, 847,691
If we take the growth of the population similar to simple interest of money deposits, then :
2, 000, 000 = P + P * 2/100 * 4
P = 2, 000, 000 / 1.08 = 1, 851, 852
In this case the answer is B