Question

the population of a country is 320000.
4% of the population immigrates every year. What will be the population of the country after 2 years?​

Answer 1

Answer:

345600

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

✦ Given :

• Population of a country is 3,20,000 evey year there is a immigration in a rate of 4%

✦ Here, rate and time of immigration is given we need to find the population after 2 years.

❐ Step 1 :

✦ Using the formula :

$\bigstar{ \underline{ \boxed{ \sf \:Amount = p\bigg(1 + \frac{r}{100}\bigg)^n}}} \bigstar$

$\begin{gathered}{ \textsf{ \textbf{Considering}}}\begin{cases} \sf{r{ (rate\%) \to \: 4\%} }\\ \sf{n(time) \to \: 2years} \\ \sf{p(principal) \to 320000}\end{cases} \end{gathered}$

✦ From the given values :

$\sf \to \: amount = 320000 \bigg(1 + \frac{4}{100} \bigg)^2$

$\sf \to \: amount =320000\bigg( \frac{104}{100} \bigg)^{2}$

$\sf \to \: amount = 32 \cancel{0000} \times \frac{104}{{100}} \times \frac{104}{{100}}$

$\sf \to \: amount =32 \times 104 \times 104$

${{ \sf{\to \: amount =346112}}}$

❐ Step 2 :

• We have got the amount increased in 2 years. Now, we need to find the population after 2 years.

So, population after 2 years is :

$\sf \to Amount + principal$

$\sf \to \: 346112 + 320000$

$\sf \to \: 666112$

$\therefore$ Population after 2 years is 666,112