The population of a particular town 4 years back was 2,500. The current population
is 4,000.
What will be the population after a period of 4 years, if the rate of growth of the
population has been kept constant and it has been compounded annually?
Answers
Given : The population of a particular town 4 years back was 2,500. The current population is 4,000. the rate of growth of the population has been kept constant and it has been compounded annually
To find : What will be the population after a period of 4 years
Solution:
Let say rate of growth = r % per annum
A = P(1 + r/100)ⁿ as rate of growth of the population has been kept constant and it has been compounded annually
Population 4 years back = 2500
Time period n = 4 years
Current population = 2500 ( 1 + r/100)⁴
=> 4000 = 2500 ( 1 + r/100)⁴
=> ( 1 + r/100)⁴ = 1.6
Current population = 4000
Population after 4 years = 4000 ( 1 + r/100)⁴
Substitute ( 1 + r/100)⁴ = 1.6
=> Population after 4 years = 4000 * 1.6
=> Population after 4 years = 6400
population after a period of 4 years = 6400
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