Question

The population of a place in the year 2000 was 48000.This showed a rate of increase of 5%per year. What would have been the population in the year 1998 and what will it be in the year 2003.

Answer 1

in year 1998the population would be 12000 and in 2003 will be60000

Answer 2

Answer:

population in 1998: 43320; population in 2003:55566

Step-by-step explanation:

population = 48000

1998= formula of decreament as in compound interest

48000( 1 - $\frac{5}{100}$$)^{2}$

=43320

2003 = 48000( 1 +$\frac{5}{100}$ $)^{2}$

=55566

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