Math, asked by ptamanna679, 2 days ago

The population of a place increased to 1,21,000 in 2003 at a rate of 10% per annum. Find the population in 2001​

Attachments:

Answers

Answered by wolverin8261
1

Answer:

a = p( 1 + r/100 )^n

n = 2003 - 2001

n = 2

so, 1,21,000 = p( 1 + 10/100)²

1,21,000 = p(110/100)²

1,21,000 = p(11/10)²

p = 1,21,000 × 100/121

p = 100,000

Answered by gaur86rekha
5

Answer:

pls mark me as a brainliest

Step-by-step explanation:

pls

drop some thanks to my all answers

hope the above picture helps you

Similar questions