Question

The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. Find:
*the population in the year 2000.
*population in 2006.

Answer 1

Hi,
Rate=5% p.a
Present population =54000
Population in 2006 i.e. after 3 yrs
=54000+[(54000×3×5) ÷100] =54000+[540×15]
=54000+8100
=62100
Population three yrs back
=54000-[(54000×3×5)] =54000-8100
=45900

Population in 2000=45900
Population in 2006=62100

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