Question

The population of a place increased to 54,000 in 2003 at a rate of 5% per annum.  Find the population in 2001 ​

Answer 1

Question.....

The population of a place increased to 54,000 in 2003 at a rate of 5% per annum.  Find the population in 2001 .

Answer...

Population in 2001 at the rate of 5%per annum = 51300 x ( 5 / 100) = 2565. = 51300 - 2565 = 48735.

Now population in 2003 = 54000. Population of a place increased at the rate of 5%per annum.

Answer 2

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• Ally Here!!

Given:

We use the formula of compound interest to find population.

A(2003)= 54,000

R= 5%

N= 2 years

i) 2001 population would be less than 2003 in two years.

• A(2003)= P(2001)(1+R/100)^n
• 54000= P(2001)(1+5/100)^2
• 54000= P(2001)(1+1/20)^2
• 54000= P(2001)(21/20)^2
• 54000=P(2001)((21 x 21)((20 x 20)
• P(2001)=(54000 x 20 x 20)/21 x 21

Population in 2001 = 48979.59 = 48980( approx.)

ii) ATQ, The population is increasing.

Therefore, population in 2005,

• A(2005)= P(1+R/100)^n
• 54000(1+5/100)^2
• 54000(1+1/20)^2
• 54000(21/20) x (21/20)
• 54000 x 441)/400
• (540 x 441)/4
• 238140/4
• 59535

Population in 2005 = 59535

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