Question

The population of a place increased to 54,000 in 2003 at a rate of 5% per annum.
i)Find the population in 2001.
ii) What would be the population in 2005?

Answer 1

$Let P be the population in 2001, i.e., 2 years ago</p><p>Then, PresentPopulation=P×(1+1005)2</p><p>⇒54000=P×100105×100105</p><p></p><p>⇒P=105×10554000×100×100=48979.59</p><p></p><p>$

Let P be the population in 2001, i.e., 2 years ago

Then, PresentPopulation=P×(1+

100

5

)

2

⇒54000=P×

100

105

×

100

105

⇒P=

105×105

54000×100×100

=48979.59

Hence, the Population in the year 2001 is 48980.