Question

The population of a place increased to 54000 in 2003 at a rate of 5% per annum, find the population in 2001.

I think there is a mi9stake in th Ncert solutions. If not please explain fast!!!!

Answer 1

hello... ☺



cσmpσund íntєrєst tσ fínd pσpulαtíσn 

α( 2003)
= 54,000,

r =5%, 

n = 2чєαrs

ín 2001 pσpulαtíσn wσuld вє lєss thαn 2003 ín twσ чєαrs.

α(2003)
= p(2001)(1+r/100)^n

54000
= p (2001)(1+5/100)²


54000
= p(2001)(1+1/20)²


54000
= p(2001)(21/20)²


54000
= p(2001)((21×21)/(20×20))


p(2001)
=( 54000×20×20)/21×21


pσpulαtíσn :-

= 48979.59
= 48980(αpp)


thank you ☺ ♥