Question

The population of a place increased to 54000 in 2003 at a rate of 5% per annum. find the population in 2001

Answer 1

Given:

we use formula of amount of compound interest to find population 

A( 2003)= 54,000,

R =

5%, 

n = 2

years

 

In 2001 Population would be less than 2003 in two years.

A(2003)= P(2001)(1+R/100)^n

54000 = P (2001)(1+5/100)²

54000 = P(2001)(1+1/20)²

54000= P(2001)(21/20)²

54000 = P(2001)((21×21)/(20×20))

P(2001)=( 54000×20×20)/21×21

Population in 2001 = 48979.59= 48980(approx)

Answer 2

hope it helps you...........