Question

the population of a place increased to 54000 in a certain year at a rate of 5% per annum. find its population two years before. what would be its population after two years?
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Answer 1

Answer:

$54000(1 + { \frac{1}{20} )}^{2}$

$54000 \times \frac{21}{20} \times \frac{21}{20}$

$135 \times 21 \times 21$

$59535$

population after 3 years

Answer 2

Answer:

59535 is your answer

Step-by-step explanation:

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