Question

The population of a small locality was 4,000 in 2010 and became 4,500 in

2011. By what percent did the population increase?​

Answer 1

$\huge\underline\mathfrak\red{Answer}$

Year 1979 population = 4,000

Year 1981 population = 4,500

Increase in population = (4,500 – 4,000) = 500

percentage of increase in population = \frac { 500 }{ 4000 } x 100 = 12.5%

⚡pika here

Answer 2

4500-4000 =500

500/4000×100= 12.5℅