Math, asked by directorgoaps, 2 months ago

The population of a small town was 1,16,000 on the last day of the year 1959. During the next year it increased by 8.5% but due to swine flu it then decreased by 10% in the following year. What was its population at the end of the year 1961?

Answers

Answered by pjnishi07
3

Step-by-step explanation:

population of a town = 1,16,000

next year increased by= 8.5%

1,16,000*8.5/100

116000*85/1000

116*85=9860

population in 1960= 116000+9860=125860

population in two years= 116000+125860

= 241860

in the following year decreased by =10%

241860*10/100=24186

population in 1961=241860-24186

=217674

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