Question

the population of a suburb is 16000 .find the rate of increase in the population if the population after two year is 17640

Answer 1

$I_{0}$=Initial Population= 16,000

Population after 2 years = $I_{2}$= 17640

The formula for increase or decrease in population is given by:

$I_{2}=I_{0}[1 +\frac{R}{100}]^t\\\\ 17,640= 16,000[ 1 +\frac{R}{100}]^2$

$\frac{1764}{1600}=[ 1 +\frac{R}{100}]^2\\\\ (\frac{42}{40})^2=[ 1 +\frac{R}{100}]^2\\\\ \frac{42}{40}=1 +\frac{R}{100}\\\\ \frac{2}{40}=\frac{R}{100}\\\\ R= \frac{200}{40} \\\\ R= 5$

Rate of increase= 5 %

Answer 2

Answer:

Please see the attached file for the answer