Math, asked by divya29081998, 5 months ago

The population of
a town 2 years ago was 62500.
Due to migration to big cities, it decreases every year at
the rate of 4%
The present population
of the town is :​

Answers

Answered by shristik529
1

population of town 2 years ago-62500

decreasing of population per year-4℅

after 2 years population decrease-8℅

8℅of 62500-5000

present population =62500-5000=57500

Answered by SKarthikeyan1123
4

Answer:

Compound Interest Formula = p(1+R/100)^n

Since the Population is decreasing R is Negative

P = 62500, R = -4, N = 2

=62500(1+(-4)/100)^2

=62500×96/100×96/100

=625×96×96/100

=57600

Hence, the present Population of the Town is 57600

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