Question

The population of a town grows uniformly at the rate of 4% every year. In how many years will the population of the town grow from 15,62,500 to 17,57,600?​

Answer 1

Answer:

increased population = 1757600

present population = 1562500

$atq \\ 1562500(1 + \frac{4}{100} ) ^{n} = 1757600 \\ ( \frac{26}{25} ) ^{n} = \frac{1757600}{1562500} \\ (\frac{26 }{25} ) ^{n} = ({ \frac{26}{25} })^{3} \\ n = 3$

Answer 2

$\green{ \fcolorbox{grey}{grey}{ \checkmark \: \textsf{Verified \: answer}}}$

• Increased Population = 1757600
• Present Population = 1562500

$\begin{gathered}atq \\ 1562500(1 + \frac{4}{100} ) ^{n} = 1757600 \\ ( \frac{26}{25} ) ^{n} = \frac{1757600}{1562500} \\ (\frac{26 }{25} ) ^{n} = ({ \frac{26}{25} })^{3} \\ n = 3\end{gathered}$