Question

The population of a town has a constant growth of 4% p.a. If its present population is 62,500, what will be its population after two years​

Answer 1

Step-by-step explanation:

Population after 2 years = P (1 + 4/100)2 = 62500 X (104/100)2

= 62500 × 26/25 X 26/25 = 100 × 26 ×26 = 67600.

Hence, the population after two years will be 67,600.

Answer 2

The question is The population of a town has a constant growth of 4% p.a. If its present population is 62,500,

we have to find what will be its population after two years.

let the present population be p =62, 500.

Constant growth rate per annum is 4%

we have to find the population after 2 years, which is T.

The formula to find the amount of people after 2 years will be

$a = p {(1 + \frac{r}{100}) }^{n}$

let's substitute the values in the formula we get

$x = 62500 {(1 + \frac{4}{100}) }^{2} \\ = 62500 ({\frac{104}{100} })^{2} \\ = 62500 \times \frac{104}{100} \times \frac{104}{100 } \\ = 62500 \times \frac{104}{100} \times \frac{104}{100} \\ = 62500 \times \frac{26}{25} \times \frac{26}{25} \\ = 100 \times 26 \times 26 \\ = 67600$

After substituting all the values in the formula and simplifying we get the value as 67600.

Therefore, it is founded that the population after 2 years will be 67600

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