The population of a town has increased from 6000 to 65000 then the increasing population is
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Late the population increases at the rate of r per year and present population is x, then
b[1+(r/100)]^3 = x =>[1+(r/100)]^3 = x/b
Also x[1+(r/100)]^3=c => x*x/b= c or x^2= bc
Hence x= Sqrt(bc)
b[1+(r/100)]^3 = x =>[1+(r/100)]^3 = x/b
Also x[1+(r/100)]^3=c => x*x/b= c or x^2= bc
Hence x= Sqrt(bc)
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