Math, asked by Arunsinghdx1418, 1 year ago

The population of a town has increased from 60000 to 65000 then the increase percent is

Answers

Answered by HETA1208
35
It's
[(65,000 - 60,000)*100] ÷ 60,000
= 83.33%
Answered by atalante
16

Solution:

The percentage increase is 8.33%

Explanation:

We have been given that the population of the town has increased from 60000 to 65000.

Hence, first of all we find the change in population which is actually the difference of 65000 and 60000.

Change in population = 65000 - 60000 = 5000

Now, we have to find the percentage increase which is given by

\text{Percentage increase} = \frac{\text{Change in population}}{\text{Initial population}} \times 100\\\\= \frac{5000}\frac{60000}\times100\\\\=\frac{25}{3}\\=8.33\%

Therefore, the percentage increase is 8.33%

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