Math, asked by adityaguptafbg718, 4 months ago

The population of a town in 1986 was 70,350. In 1987 it was 1,05,525. Find the
percentage increase in the population in 1987.

Answers

Answered by nitaranandakishor555
4

hope it helps....thanks.

Attachments:
Answered by sateesh141996
3

Answer:

% increase = 50%

Step-by-step explanation:

Population in 1986 = 70,350

Population in 1987 = 1,05,525

% increase = [ ( 105525 - 70350) / 70350 ] *100

= (35175/ 70350)*100

= 0.5 *100

= 50%

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