Question

The population of a town in 2005 was 18,00,000 and in 2006 it became 21,00,000. Find the percentage increase in population.

plz example step by step​

Answer 1

The percentage increase would be 16.67%

Given:-

• The population in 2005 = 1800000
• While, the population in 2006 = 2100000

Thus the percentage increase in population

$= \frac{population \: in \: 2006 - population \: in \: 2005}{population \: in \: 2005} \times 100$

$= \frac{2100000 - 1800000}{1800000} \times 100$

$= \frac{300000}{1800000} \times 100$

$= \frac{1}{6} \times 100$

$= 16.67$

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Answer 2

Answer:

$16 \times \frac{2}{3} \%$

This is your answer.