Question

The population of a town in 2005 was 1800000 and in 2009 was 2100000. Find the
increase per cent.

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Answer 1

Answer:

Step-by-step explanation:

2100000- 1800000

=300000

=300000÷1800000×100

=16.6% answer.

Answer 2

Answer:

16.66 %

Step-by-step explanation:

Population in 2005 = 1800000

Population in 2009 = 2100000

Increase in population = 2100000 - 1800000 =300000

Increase % = $\frac{300000}{1800000} * 100 = 16.66 %$