Question

The population of a town in three consecutive decade are 1 lakh, 1.4 lakh, 1.68 lakh respectively.The population

Answer 1

Answer:

Step-by-step explanation:

Population in 1 year = 100000

Population in 2 year= 140000

Increment = 40000

Growth rate= 40000/100000= 0.4

Population in 3 year= 168000

Increment=28000

Growth rate= 28000/140000=0.2

Geometric mean=√(.4×0.2)=.2828=28.28%

Population in 4th decade=168000×(1+.2828)=2.15 lakhs. [Ans]∆

Answer 2

Concept

The mean value (GM) is that the average value or mean which signifies the central tendency of the set of numbers by finding the merchandise of their values.

Given

The population of a town in three consecutive decade are:

1 lakh, 1.4 lakh, 1.68 lakh.

To find

The population in 4th decade.

Explanation

Population in 1 decade=100000

Population in 2 decade= 140000

Increment=40000

Growth rate=40000/100000=0.4

Population in 3 decade=168000

Increment=28000

Growth rate=28000/140000=0.2

Geometric mean=$\sqrt{0.4*0.2}$

=$\sqrt{0.08}$

=0.2828

=28.28%

population in 4th decade=168000*(1+0.2828)

=168000(1.2828)

=2.15 lakh.

Hence if the population in three consecutive decade are 1 lakh, 1.4 lakh, 1.68 lakh then the population in 4th decade is 2 lakh 15 thousand.

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