The population of a town increase at annual rate 8 %. If present population of town is 7,496 the find population of town before 2 years.
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let the population of a town 2 years ago be x.
Then, it's present population =108%of x
= (x * 108/100)
= 27/25x.
27/25x =7496
x= (7496*27/25)
x = 8095.68
hence, the population of the town 2 year ago was 8095.68
Then, it's present population =108%of x
= (x * 108/100)
= 27/25x.
27/25x =7496
x= (7496*27/25)
x = 8095.68
hence, the population of the town 2 year ago was 8095.68
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