Question

The population of a town increase by 10% annually. If it's present population is. 80000, what will be population after 2 years ?

Answer 1

rate= 10℅
p= 80000
Time= 2 years
A = p(1+r/100)^2
A= 80000( 1+10/100)^2
A=80000×110/100×110/100
A=96800
it's percentage will be 96800/80000×100℅
= 121℅
It's population will be 96800

HOPE IT HELPS YOU

Answer 2

hope this helps.. ..