Math, asked by kanika771749, 1 year ago

the population of a town increase by 10percentage annually if the present population is 22000 ,find its population a year ago​

Answers

Answered by abdulqadir52
2

the answer is 2000

if it is correct then please thank me

Answered by Thûgłife
5

Step-by-step explanation:

Here is your answer :-

Here is your answer :-Present population of town = 22000

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%Let the population 1 year ago be x .

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%Let the population 1 year ago be x .Now,

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%Let the population 1 year ago be x .Now,(x + 10% of x) = 22000

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%Let the population 1 year ago be x .Now,(x + 10% of x) = 22000(x + x/10) = 22000

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%Let the population 1 year ago be x .Now,(x + 10% of x) = 22000(x + x/10) = 2200011x/10 = 22000

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%Let the population 1 year ago be x .Now,(x + 10% of x) = 22000(x + x/10) = 2200011x/10 = 22000x = 22000 × 10/11

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%Let the population 1 year ago be x .Now,(x + 10% of x) = 22000(x + x/10) = 2200011x/10 = 22000x = 22000 × 10/11x = 20000

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%Let the population 1 year ago be x .Now,(x + 10% of x) = 22000(x + x/10) = 2200011x/10 = 22000x = 22000 × 10/11x = 20000So,

Here is your answer :-Present population of town = 22000Rate of increase in population annually = 10%Let the population 1 year ago be x .Now,(x + 10% of x) = 22000(x + x/10) = 2200011x/10 = 22000x = 22000 × 10/11x = 20000So,The population 1 year ago will be 20000

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