the population of a town increase by 5% during the first year and by 7% during the second year.at the end of second year the population was 40446 .what was the population at the beginning.
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rate of increase in population in the second year = 7%
population at the end of second year = 40446
P(1+i) = A
P= population at the beginning, i = rate of increase per annum, A= population at the end of the year
P(1+7/100) = 40446
P(1+0.07) = 40446
P(1.07) = 40446
P= 40446/1.07 = 37800 (at the beginning of second year).
so the ending of the first will be 37800
rate of increase in population in the first year = 5℅
P(1+5/100) = 37800
P(1+0.05) = 37800
P(1.05) = 37800
P= 37800/1.05= 36000(at the beginning of First year).
so yhe answer is 36000
population at the end of second year = 40446
P(1+i) = A
P= population at the beginning, i = rate of increase per annum, A= population at the end of the year
P(1+7/100) = 40446
P(1+0.07) = 40446
P(1.07) = 40446
P= 40446/1.07 = 37800 (at the beginning of second year).
so the ending of the first will be 37800
rate of increase in population in the first year = 5℅
P(1+5/100) = 37800
P(1+0.05) = 37800
P(1.05) = 37800
P= 37800/1.05= 36000(at the beginning of First year).
so yhe answer is 36000
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36000
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