Question

the population of a town increase by 8% annually. if the present population is 54000,what was it year ago?

Answer 1

Let the population was x

so, population before 1 year was 100% of x

population after 1 year was 100% of x + 8% of x = 108% of x = 54000

So, 108% of x = 54000

108x/100 = 54000

108x = 5400000

x = 5400000/108

x = 50000

Hence population before 1 year was 50000.

Answer 2

8/100×54000=4320
54000-4320=39680