Question

the population of a town increased by 10.5%every year .If its present population is 795600 .What was it a year ago???

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Answer 1

Answer:

Step-by-step explanation:

Present population(pt)= 795600

Rate of increment in each year(R)=10.5%

Time (t)= 1 year

We know that,

Pt= P(1+(R/100))^t

or, 795600= P(1+(10.5/100))^1

or, 795600*100=P110.5

P= 720000

The population was 720000 before a year

Answer 2

Step-by-step explanation:

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