Question

the population of a town increased by 10% annually . If its present population is 60000 what will be the population after 2yrs

Answer 1

72600 is the answer.
Explanation :
After first year 10 % increase.
So total 66000
Next year, 10 % of 66000 is 6600, making total 72600, at the end of 2nd year.

Answer 2

Rate =10% Time = 2 years
Present Population = 60000
Population after two years
$= 60000 \times (1 + r \div 100) {}^{n}$
$= 60000 \times (1 + 10 \div 100) {}^{2}$
$= 60000 \times( 110 \div 100) \times (110 \div 100)$
$= 6 \times 110 \times 110$
$= 72600$



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