Question

The population of a town increased by 10% annually if the present population is 60000 what will be the population after 2 year please answer fast urgent

Answer 1

Current Population = 60,000

At the end of 1st year, population of town = Current Population + 10% of Current Population = 60000 + (10/100)*60000 = 60000 + 6000 = 66,000

At the end of 2nd year, population of town = Population after 1st year + 10% of Population after 1st year = 66000 + (10/100)*66000 = 66000 + 6600 = 72,600

Therefore population of the town after 2 years = 72,600 ——> Answer

Answer 2

Answer:

72600

Step-by-step explanation:

p = 60000(1.1)² = 72600