Question

the population of a town increased by 10% annually if the present population is 22000 find the populations year ago​

Answer 1

Answer:

18,181

Step-by-step explanation:

22000/(1+10/100)

22000 * 10/11*10/11

181.81*100

= 18181

Answer 2

Given:-

• the population of a town increased by 10% annually if the present population is 22000.

To find:-

• find the populations year ago....?

Solutions:-

• Let the population of the town one year ago = x.

Now,

The population of the town increase by 10% annually.

According to the questions;

Present population = x + 10% of x

= x + 10/100 × x

= x + x/10

= 10x + x / 10

= 11x/10

present population of the town = 22000

So,

⟹ 11x/10 = 22000

⟹ 11x = 22000 × 10

⟹ 11x = 220000

⟹ x = 220000/11

⟹ x = 20000

Hence, the population of the town 1 year ago = 20000.