Question

The population of a town increased by 10% annually if the present population is 22000 what was it a year ago?

Answer 1

Let the tot. population a year ago = x

10/100x + x = 22000

10x + 100x = 2200000

110x = 2200000

x = 20000...................ANS

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Answer 2

HELLO FRIEND HERE IS YOUR ANSWER,,,,,,,,,

By applying the formula of compound interest we can make the following assumptions and calculate them for the same. You'll come across this formulae.........

Let us take it as "x" years and Total population to find be "Y" and let "PP" be as present population , we'll get this ,,,

$\boxed{\bf{PP = Y \times [1 - \frac{r}{100}]^x}}$

Now, for population changes before "1" years ago, substitute this into "x" years ,,,

$\bf{22000 = Y \times [1 + \frac{10}{100}]^1}$

$\bf{22000 = Y \times [1 + 0.1]^1}$

$\bf{22000 = Y \times [1.1]^1}$

$\bf{22000 = Y \times [1.1]}$

$\boxed{\bf{\therefore \: \: Y = 20000}}$

Therefore the answer is ,,,

$\boxed{Y = 20000}$

HOPE THIS HELPS YOU AND CLEARS THE DOUBTS FOR CALCULATING THE TIMES OF YEAR BY THIS FORMULAE!!!!!!!