the population of a town increased by 10 percentin 2011 it was 75900in the begginig of 2012 what was the beginning of 2011
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Let the population in 2011 be x.
Then, 75900 = x*(1+10/100)
75900 = x*110/100
75900*100/110 = x
6900*10 = x
69000 = x.
Therefore, the population in 2011 was 69000.
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Then, 75900 = x*(1+10/100)
75900 = x*110/100
75900*100/110 = x
6900*10 = x
69000 = x.
Therefore, the population in 2011 was 69000.
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Answered by
1
Answer:
The answer is 69000
Explanation:
Let the beginning of 2011 be a.
a (1+10/100)=75900
a×110/100=75900
a=75900×100/110
a=75900×10/11
a=6900×10
a=69000
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