Question

The population of a town increased by 5% annually . if the present population is 4410. what it was 2 years ago?

Answer 1

using compounding formula
$a + b + \frac{ab}{100}$
we have
5+5+25/100=10.25%
so if the population 2 yrs ago be x
then
x+10.25x/100=4410
or 110.25x=441000
x=4000 ans

Answer 2

4000

Step-by-step explanation:5%= 1/20

20 21

20 21

400 441

441----->4410

1 ------> 10

400*10=4000