the population of a town increased by 8% annually if the present population is 54000 what was it a year ago?
Answers
Answered by
404
Hi ,
Let the last year population = x
Present year population = 54000
Increased percent = g = 8 %
Present population = last year population × ( 100 + g )/100
54000 = x × ( 100 + 8 ) / 100
54000 = x × ( 108 / 100 )
( 54000 × 100 ) / 108 = x
50000 = x
Therefore,
The last yeat population = x = 50000
I hope this helps you.
:)
Let the last year population = x
Present year population = 54000
Increased percent = g = 8 %
Present population = last year population × ( 100 + g )/100
54000 = x × ( 100 + 8 ) / 100
54000 = x × ( 108 / 100 )
( 54000 × 100 ) / 108 = x
50000 = x
Therefore,
The last yeat population = x = 50000
I hope this helps you.
:)
Answered by
140
Let the last year population = x
Present year population = 54000
Inreased percent = g = 8 %
Present population = last year population × ( 100 + g )/100
54000 = x × ( 100 + 8 ) / 100
54000 = x × ( 108 / 100 )
( 54000 × 100 ) / 108 = x
50000 = x
Therefore,
The last yeat population = x = 50000
hope this helps you.
thanxx and be brainly.............................
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