Math, asked by harshdeeps336, 12 hours ago

The population of a town increased by 8% in the first year. Then, due to an epidemic in the second year, the population decreased by 5%. Find the population after 2 years if the current population is 100000.

Answers

Answered by abhijeetkumardas99
0

Answer:

For 1st year,

P=100000,R=8%,T=1 year

SI=P*R*T/100

=100000*8*1/100

=8000

So ,population after 1st year=100000+8000=108000

For 2nd year,

P=108000,R=5%,T=1 year

SI=108000*5*1/100

=5400

So, Total Population after 2 years=108000-5400=102600 Answer.

Answered by shiwkishor
0

Step-by-step explanation:

Population after two years =

100000 ( 1.08 ) ( 0.95) = 102600

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