The population of a town increased by 8% in the first year. Then, due to an epidemic in the second year, the population decreased by 5%. Find the population after 2 years if the current population is 100000.
Answers
Answered by
0
Answer:
For 1st year,
P=100000,R=8%,T=1 year
SI=P*R*T/100
=100000*8*1/100
=8000
So ,population after 1st year=100000+8000=108000
For 2nd year,
P=108000,R=5%,T=1 year
SI=108000*5*1/100
=5400
So, Total Population after 2 years=108000-5400=102600 Answer.
Answered by
0
Step-by-step explanation:
Population after two years =
100000 ( 1.08 ) ( 0.95) = 102600
Similar questions