Question

the population of a town increases 10% annually if its present population is 60000 , what will be the population after 2 years ​

Answer 1

Step-by-step explanation:

Present population of town is = 60000

Present population of town is = 60000 Annually population increases by = 10%

Present population of town is = 60000 Annually population increases by = 10% So, Population after 2 years = present population

Present population of town is = 60000 Annually population increases by = 10% So, Population after 2 years = present population × [(100 + increased %)/100] years = 60000 ×

Present population of town is = 60000 Annually population increases by = 10% So, Population after 2 years = present population × [(100 + increased %)/100] years = 60000 × (100+10)/100 × (100+10)/100 = 60000 × 110/100 ×

Present population of town is = 60000 Annually population increases by = 10% So, Population after 2 years = present population × [(100 + increased %)/100] years = 60000 × (100+10)/100 × (100+10)/100 = 60000 × 110/100 × 110/100 = 60000 × 11/10 × 11/10 = 72600

Present population of town is = 60000 Annually population increases by = 10% So, Population after 2 years = present population × [(100 + increased %)/100] years = 60000 × (100+10)/100 × (100+10)/100 = 60000 × 110/100 × 110/100 = 60000 × 11/10 × 11/10 = 72600 ∴ After 2 years population will be 72600.

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