Question

The population of a town increases 4% during the first year and 5% during the second year,the population is 104832. What was the population at the beginning.

Answer 1

9030000 is the answer

Answer 2

Answer:

96000

Step-by-step explanation:

Let the initial population be x

The population of a town increases 4% during the first year

So, Population after first year = $x+4\% x=x+\frac{4}{100}x=1.04x$

The population of a town increases by 5% during the second year

So, Population after second year  = $1.04x+5\% (1.04x)=1.092x$

Now we are given that the population is 104832.

So, $1.092x=104832$

$x=\frac{104832}{1.092}$

$x=96000$

Hence the population at the beginning is 96000