Math, asked by shashiy2441998, 1 year ago

the population of a town increases 5% for first year and 4% in the second year find the population at end of 2 years if the population was 360000 at beginning of first year​

Answers

Answered by Anonymous
189

AnswEr :

\frak{Given}\begin{cases}\tt{Old \:Population = 360000}\\\tt{First\:Year=5\%}\\ \tt{Second\:Year=4\%}\\\tt{New\: Population\:at \:the \:end \:of\:2\:years.} \end{cases}

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\underline{\bigstar\:\textsf{According to the Question Now :}}

:\implies\sf New\:Population = Old\: Population \times (100+Increase)\% \times (100+Increase)\%\\\\\\:\implies\sf New\:Population = 360,000\times (100+5)\% \times (100+4)\%\\\\\\:\implies\sf New\:Population =360,000 \times 105\% \times 104\%\\\\\\:\implies\sf New\:Population =360,000 \times \dfrac{105}{100} \times \dfrac{104}{100}\\\\\\:\implies\sf New\:Population =36\times105 \times 104\\\\\\:\implies\sf New\:Population =36 \times 10,920\\\\\\:\implies\boxed{\textsf{New\:Population =\textbf{393,120}}}

\therefore\:\underline{\textsf{Population at the end of 2 years is \textbf{393,120.}}}

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\boxed{\begin{minipage}{7 cm}\underline{\text{Some Important Formulae Related to it :}}\\ \\\sf Increase = Old Population\times(100+\sf Increase)\%\\ \\Decrease=Old \:Population\times(100-Decrease\%)\end{minipage}}

Answered by GLAmorOUS
34

<body bgcolor=b>

\huge\mathbb\pink{GLAmorOUS..!!}

<font color=white>

Given values :-

♥️ Population in first year = 3,60,000

♥️ Population ↑ in first year = 5%

♥️ Population ↑ in second year = 4%

♥️ Population at the end of 2 years = ?

New population = old population × ( 100 + population in 1st year )% × ( 100 + population in 2nd year )%

New population = 3,60,000 × ( 100 + 5 )% × ( 100 + 4 )%

⭐New population = 3,60,000 × 105% × 104%

⭐New population = 3,60,000 × 105 / 100 × 104 / 100

New population = 36 × 105 × 104

New population = 36 × 10,920

\huge{\boxed{\mathfrak\pink{\fcolorbox{red}{lightgreen}{New\:population\:=\:3,93,120}}}}

:. At the end of 2 years = 3,93,120 population

<marquee>GLAmorOUS</marquee>

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